User Input not working with keyboard.nextLine() and String (Java)

User Input not working with keyboard.nextLine() and String (Java)

For you code Change nextLine(); to next(); and it will work.

System.out.println(Was that in Celsius or Fahrenheit?);
    System.out.print((Enter C for Celsius and F for Fahrenheit) );
    type = keyboard.next();

to get an idea for you to what happened was this:

• nextLine(): Advances this scanner past the current line and returns the input that was skipped.
• next(): Finds and returns the next complete token from this scanner.

Also like the many of the answers says use equals() instead of using ==

The == checks only the references to the object are equal. .equal() compares string.

Read more Here

Never use Scanner#nextLine after Scanner#nextInt. Whenever you hit enter button after Scanner#nextInt than it will skip the Scanner#nextLine command. So,
Change from

 int temp = keyboard.nextInt();

to

 int temp = Integer.parseInt(keyboard.nextLine());

User Input not working with keyboard.nextLine() and String (Java)

.nextInt() does not read the end of line character n.

You need to put a keyboard.nextLine() after the .nextInt() and then it will work.