Setting an int to Infinity in C++
Setting an int to Infinity in C++
Integers are inherently finite. The closest you can get is by setting a
to int
s maximum value:
#include <limits>
// ...
int a = std::numeric_limits<int>::max();
Which would be 2^31 - 1
(or 2 147 483 647
) if int
is 32 bits wide on your implementation.
If you really need infinity, use a floating point number type, like float
or double
. You can then get infinity with:
double a = std::numeric_limits<double>::infinity();
Integers are finite, so sadly you cant have set it to a true infinity.
However you can set it to the max value of an int, this would mean that it would be greater or equal to any other int, ie:
a>=b
is always true.
You would do this by
#include <limits>
//your code here
int a = std::numeric_limits<int>::max();
//go off and lead a happy and productive life
This will normally be equal to 2,147,483,647
If you really need a true infinite value, you would have to use a double or a float. Then you can simply do this
float a = std::numeric_limits<float>::infinity();
Additional explanations of numeric limits can be found here
Happy Coding!
Note: As WTP mentioned, if it is absolutely necessary to have an int that is infinite you would have to write a wrapper class for an int and overload the comparison operators, though this is probably not necessary for most projects.
Setting an int to Infinity in C++
int
is inherently finite; theres no value that satisfies your requirements.
If youre willing to change the type of b
, though, you can do this with operator overrides:
class infinitytype {};
template<typename T>
bool operator>(const T &, const infinitytype &) {
return false;
}
template<typename T>
bool operator<(const T &, const infinitytype &) {
return true;
}
bool operator<(const infinitytype &, const infinitytype &) {
return false;
}
bool operator>(const infinitytype &, const infinitytype &) {
return false;
}
// add operator==, operator!=, operator>=, operator<=...
int main() {
std::cout << ( INT_MAX < infinitytype() ); // true
}