python – django MultiValueDictKeyError error, how do I deal with it

Use the MultiValueDicts get method. This is also present on standard dicts and is a way to fetch a value while providing a default if it does not exist.

is_private = request.POST.get(is_private, False)

Generally,

my_var = dict.get(<key>, <default>)

Choose what is best for you:

1

is_private = request.POST.get(is_private, False);

If is_private key is present in request.POST the is_private variable will be equal to it, if not, then it will be equal to False.

2

if is_private in request.POST:
    is_private = request.POST[is_private]
else:
    is_private = False

3

from django.utils.datastructures import MultiValueDictKeyError
try:
    is_private = request.POST[is_private]
except MultiValueDictKeyError:
    is_private = False

python – django MultiValueDictKeyError error, how do I deal with it

You get that because youre trying to get a key from a dictionary when its not there. You need to test if it is in there first.

try:

is_private = is_private in request.POST

or

is_private = is_private in request.POST and request.POST[is_private]

depending on the values youre using.