java – Fill an array with random numbers

java – Fill an array with random numbers

You can use IntStream ints() or DoubleStream doubles() available as of java 8 in Random class. something like this will work, depends if you want double or ints etc.

Random random = new Random();

int[] array = random.ints(100000, 10,100000).toArray();

you can print the array and youll get 100000 random integers.

You need to add logic to assign random values to double[] array using randomFill method.

Change

 public static double[] list(){
    anArray = new double[10];   
    return anArray;
 }

To

 public static double[] list() {
    anArray = new double[10];
    for(int i=0;i<anArray.length;i++)
    {
        anArray[i] = randomFill();
    }
    return anArray;
}

Then you can call methods, including list() and print() in main method to generate random double values and print the double[] array in console.

 public static void main(String args[]) {

list();
print();
 }

One result is as follows:

-2.89783865E8 
1.605018025E9 
-1.55668528E9 
-1.589135498E9 
-6.33159518E8 
-1.038278095E9 
-4.2632203E8 
1.310182951E9 
1.350639892E9 
6.7543543E7 

java – Fill an array with random numbers

This seems a little bit like homework. So Ill give you some hints. The good news is that youre almost there! Youve done most of the hard work already!

  • Think about a construct that can help you iterate over the array. Is there some sort of construct (a loop perhaps?) that you can use to iterate over each location in the array?
  • Within this construct, for each iteration of the loop, you will assign the value returned by randomFill() to the current location of the array.

Note: Your array is double, but you are returning ints from randomFill. So theres something you need to fix there.

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