How do I remove the file suffix and path portion from a path string in Bash?

Heres how to do it with the # and % operators in Bash.

$ x=/foo/fizzbuzz.bar
$ y=${x%.bar}
$ echo ${y##*/}
fizzbuzz

${x%.bar} could also be ${x%.*} to remove everything after a dot or ${x%%.*} to remove everything after the first dot.

Example:

$ x=/foo/fizzbuzz.bar.quux
$ y=${x%.*}
$ echo $y
/foo/fizzbuzz.bar
$ y=${x%%.*}
$ echo $y
/foo/fizzbuzz

Documentation can be found in the Bash manual. Look for ${parameter%word} and ${parameter%%word} trailing portion matching section.

look at the basename command:

NAME=$(basename /foo/fizzbuzz.bar .bar)

instructs it to remove the suffix .bar, results in NAME=fizzbuzz

Pure bash, done in two separate operations:

Remove the path from a path-string:

path=/foo/bar/bim/baz/file.gif

file=${path##*/}  
#$file is now file.gif

Remove the extension from a path-string:
```
base=${file%.*}
#${base} is now file.
```