c++ – expression preceding parentheses of apparent call must have (pointer-to-) function type

c++ – expression preceding parentheses of apparent call must have (pointer-to-) function type

For anyone else this might also be because of redefinition of a method or property name. i.e a property and method might have the same name

The error indicates trying to call a function max() that is not defined as a function. Change parenthesis after const keyword to after the identifier max:

T max const()...

to

T max() const ...

c++ – expression preceding parentheses of apparent call must have (pointer-to-) function type

• Add required header inclusion and using
• Add : after public
• Move const to proper position
• #include <iostream>
using std::cout;
using std::endl;template <typename T>
  class Arithmetic {
  T _a;
  T _b;
  Arithmetic() {};
  public:
  Arithmetic(T a, T b) :_a(a), _b(b) {};
  T max() const { return _a + _b; };
  T minus() const { return _a – _b; };
  };int main() {
  Arithmetic<int> ar(5,6);
  cout << ar.max() << endl;
  }

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